The Laplace Transform of t sinht is equal to 2s/(s2-1)2. The Laplace of the product tsinh t is denoted by L{t sinht}, and its formula is given as follows:
$\boxed{L\{t \sinh t\} = \dfrac{2s}{(s^2-1)^2}}$
More generally, L{t sinhat} = 2as/(s2-a2)2. In this post, we will find the Laplace transform of tsinh(at).
Table of Contents
Laplace of t sinht
Answer: The Laplace of tsinht is L{t sinht} = 2s/(s2-1)2.
Explanation:
By the multiplication by t Laplace transform formula, we will find the Laplace transform of t sinht. If L{f(t)}=F(s), then this formula states that
$L\{t f(t)\} = – \dfrac{d}{ds}(F(s))$ …(∗)
Step 1: Put f(t) = sinht
∴ F(s) = L{f(t)} = L{sinht} = 1/(s2-1) by the Laplace of sinh(at).
Step 2: Now using (∗) the Laplace transform of tsinh(t) is
$L\{t\sinh t\} = – \dfrac{d}{ds}\left(\dfrac{1}{s^2-1}\right)$
Step 3: By the quotient rule of derivatives, it follows that
$L\{t\sinh t \}$ $= – \dfrac{(s^2-1)\frac{d}{ds}(1)-1 \frac{d}{ds}(s^2-1)}{(s^2-1)^2}$
$= – \dfrac{(s^2-1)\cdot 0- 1\cdot 2s}{(s^2-1)^2}$
$= – \dfrac{-2s}{(s^2-1)^2}$
$= \dfrac{2s}{(s^2-1)^2}$.
So the Laplace transform of tsinh t is equal to 2s/(s2-1)2.
What is L{t sinht}? Summary: L{t sinh t} = 2s/(s2-1)2. |
More Laplace Transforms:
Laplace transform of sinh(at) | a/(s2-a2) |
Laplace transform of sin t: | 1/(s2+1) |
Laplace transform of sin(t)/t: | tan-1(1/s) |
Laplace transform of cos t: | s/(s2+1) |
Laplace transform of t cost: | (s2-1)/(s2+1)2 |
Laplace transform of cos(t)/t: | Does Not Exist |
What is the Laplace Transform of t sinh(at)?
Answer: The Laplace transform of t sinhat is 2as/(s2-a2)2. |
Proof:
As L{sinh at} = a/(s2-a2), using the above formula (∗), the Laplace of tsinh(at) is equal to
$L\{t\sinh(at)\} = – \dfrac{d}{ds}\left(\dfrac{a}{s^2-a^2}\right)$
= $- \dfrac{(s^2-a^2)\frac{d}{ds}(a)-a \frac{d}{ds}(s^2-a^2)}{(s^2-a^2)^2}$
= $- \dfrac{(s^2-a^2)\cdot 0-a \cdot 2s}{(s^2-a^2)^2}$
= $- \dfrac{-2as}{(s^2-a^2)^2}$
= $\dfrac{2as}{(s^2-a^2)^2}$.
Therefore, the Laplace transform of tsinh(at) is 2as/(s2-a2)2.
Also Read:
Laplace transform of (1-sint)/t
Laplace transform of (1-cost)/t
FAQs
Answer: The Laplace transform of t sinht is 2s/(s2-1)2, that is, L{t sinht} = 2s/(s2-1)2.
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