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SN Dey Class 11 Differentiation Short Answer Type Questions Solutions
SN Dey class 11 Differentiation short answer type questions Ex 1 solutions:
Ex 1: Examine whether f(x)=|x+1| has a derivative at x=-1.
Solution:
As $Lf'(-1) \neq Rf'(-1)$, we conclude that f(x)=|x+1| has no derivative at x=-1.
SN Dey class 11 Differentiation short answer type questions Ex 2 solutions:
Ex 2: If the derivative of f(x) at x=a is $f'(a)$, show that
$\lim\limits_{x \to a}\dfrac{xf(a)-af(x)}{x-a}$ $=f(a)-af(a)$
Solution:
SN Dey class 11 Differentiation short answer type questions Ex 3 solutions:
Ex 3: Find from the first principle, the derivatives of the following function:
Ex 3.(i): From the first principle, find the derivative of x3.
Solution:
Ex 3.(ii): From the first principle, find the derivative of x6.
Solution:
Derivative of square root of x : The derivative of root x is 1/2√x. |
Ex 3.(iii): From the first principle, find the derivative of √x.
Solution:
Ex 3.(iv): From the first principle, find the derivative of tan $\frac{x}{2}$.
Solution:
Ex 3.(v): From the first principle, find the derivative of sec 3x.
Solution:
Ex 3.(vi): From the first principle, find the derivative of sin 4x.
Solution:
Ex 3.(vii): From the first principle, find the derivative of sin x°.
Solution:
Ex 3.(viii): From the first principle, find the derivative of 1/√x.
Solution:
Ex 3.(ix): From the first principle, find the derivative of e3x.
Solution:
Ex 3.(x): From the first principle, find the derivative of 3√x.
Solution:
Ex 3.(xi): From the first principle, find the derivative of log 3x.
Solution:
Ex 4: Find from the definition of the differential coefficients of the following function:
Ex 4.(i): y=x+$\frac{1}{x}$ at x=1.
Solution:
Ex 4.(ii): y=4 at x=3.
Solution:
Ex 4.(iii): y=$\frac{1}{2x+3}$ at x=0.
Solution:
Ex 4.(iv): y=sec 2x at x=$\frac{\pi}{6}$.
Solution:
Ex 4.(v): y=√x at x=2.
Solution:
Ex 4.(vi): y=x2/3 at $x=\frac{1}{27}$.
Solution:
Ex 4.(vii): y=e-2x at x=0.
Solution:
Ex 4.(viii): y=cot $\frac{x}{2}$ at x=$\pi$.
Solution:
Ex 4.(ix): y=cos 2x at x=$\frac{\pi}{4}$.
Solution:
Ex 6: Differentiate the following functions with respect to x:
Ex 6.(i): 10x ⋅ x10
Solution: The derivative of 10x ⋅ x10 is equal to
d/dx(10x ⋅ x10) = 10x d/dx(x10) + x10 d/dx(10x) , by the product rule of derivatives.
= 10x ⋅ 10x10-1 + x10⋅10x loge10
= 10x+1 ⋅x9 + x10⋅10x loge10
Ex 6.(ii): x3log x
Solution:
d/dx(x3 log x) = x3 d/dx(log x) + log x d/dx(x3)
= x3 ⋅ 1/x + log x ⋅ 3x2
= x2 + 3x2 log x
= x2 (1 + 3log x)
Ex 6.(iii): ex tan x
Solution: The derivative of ex tan x is equal to
d/dx(ex tan x) = ex d/dx(tan x) + tan x d/dx(ex) , by the product rule of derivatives.
= ex ⋅ sec2x + tan x ⋅ ex
= ex (tan x + sec2x)
Ex 6.(iv): √x log √x
Solution:
d/dx(√x log √x) = √x ⋅ d/dx(log √x) + log √x ⋅ d/dx(√x)
$=\sqrt{x} \frac{1}{\sqrt{x}} \frac{d}{dx}(\sqrt{x})$ $+\log \sqrt{x} \frac{d}{dx}(\sqrt{x})$
$=\frac{d}{dx}(x^{1/2}) (1+\log \sqrt{x})$
$=\frac{1}{2} x^{1/2-1} (1+\log \sqrt{x})$
$=\frac{1}{2\sqrt{x}} (1+\log \sqrt{x})$
Ex 6.(v): (x2+1)ex
Solution:
d/dx{(x2+1)ex} = (x2+1) d/dx(ex) + ex d/dx(x2+1)
= (x2+1) ex + ex (2x+0)
= ex (x2+1+2x)
= ex (x+1)2
Ex 6.(vi): ex sec x
Solution:
The derivative of ex sec x is equal to
d/dx(ex sec x) = ex d/dx(sec x) + sec x d/dx(ex) , by the product rule of derivatives.
= ex ⋅ sec x tan x + sec x ⋅ ex
= ex sec x (tan x + 1)
Ex 6.(vii): (2x-5)(x2+2)
Solution:
Ex 6.(viii): cosec x ⋅ cot x
Solution:
The derivative of cosec x ⋅ cot x is equal to
d/dx(cosec x ⋅ cot x) = cosec x d/dx(cot x) + cot x d/dx(cosec x) , by the product rule of derivatives.
= cosec x ⋅ (-cosec2 x) + cot x ⋅ (-cosec x cot x)
= -cosec x (cosec2x+cot2x)
Ex 6.(ix): (sin x +sec x)(cos x +cosec x)
Solution:
The derivative of (sin x +sec x)(cos x +cosec x) is equal to
d/dx[(sin x +sec x)(cos x +cosec x)]
= (sin x +sec x) d/dx(cos x +cosec x) + (cos x +cosec x) d/dx(sin x +sec x)
= (sin x +sec x) (-sin x -cosec x cot x) + (cos x +cosec x) (cos x +sec x tan x)
Ex 6.(x): sec3 x
Solution: The derivative of sec3x is equal to
d/dx(sec3 x) = 3 sec2 x ⋅ d/dx(sec x)
= 3 sec2 x ⋅ sec x tan x
= 3 sec3 x tan x
Ex 6.(xi): √xex sec x
Solution:
Ex 6.(xii): xtan x log x
Solution:
Ex 6.(xiii): x cos x + 2x sec x
Solution:
The derivative of x cos x + 2x sec x is equal to
d/dx(x cos x + 2x sec x) = d/dx(x cos x) + d/dx(2x sec x)
= x d/dx(cos x) + cos x d/dx(x) + 2x d/dx(sec x) + sec x d/dx(2x)
= x sin x + cos x ⋅ 1 + 2x sec x tan x + sec x ⋅ 2xloge2
= x sin x + cos x + 2x sec x (tan x + loge2)
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